Metamath Proof Explorer


Theorem symgmatr01lem

Description: Lemma for symgmatr01 . (Contributed by AV, 3-Jan-2019)

Ref Expression
Hypothesis symgmatr01.p ⊢ 𝑃 = ( Base ‘ ( SymGrp ‘ 𝑁 ) )
Assertion symgmatr01lem ( ( 𝐾 ∈ 𝑁 ∧ 𝐿 ∈ 𝑁 ) → ( 𝑄 ∈ ( 𝑃 ∖ { 𝑞 ∈ 𝑃 ∣ ( 𝑞 ‘ 𝐾 ) = 𝐿 } ) → ∃ 𝑘 ∈ 𝑁 if ( 𝑘 = 𝐾 , if ( ( 𝑄 ‘ 𝑘 ) = 𝐿 , 𝐴 , 𝐵 ) , ( 𝑘 𝑀 ( 𝑄 ‘ 𝑘 ) ) ) = 𝐵 ) )

Proof

Step Hyp Ref Expression
1 symgmatr01.p ⊢ 𝑃 = ( Base ‘ ( SymGrp ‘ 𝑁 ) )
2 simpll ⊢ ( ( ( 𝐾 ∈ 𝑁 ∧ 𝐿 ∈ 𝑁 ) ∧ 𝑄 ∈ ( 𝑃 ∖ { 𝑞 ∈ 𝑃 ∣ ( 𝑞 ‘ 𝐾 ) = 𝐿 } ) ) → 𝐾 ∈ 𝑁 )
3 eqeq1 ⊢ ( 𝑘 = 𝐾 → ( 𝑘 = 𝐾 ↔ 𝐾 = 𝐾 ) )
4 fveq2 ⊢ ( 𝑘 = 𝐾 → ( 𝑄 ‘ 𝑘 ) = ( 𝑄 ‘ 𝐾 ) )
5 4 eqeq1d ⊢ ( 𝑘 = 𝐾 → ( ( 𝑄 ‘ 𝑘 ) = 𝐿 ↔ ( 𝑄 ‘ 𝐾 ) = 𝐿 ) )
6 5 ifbid ⊢ ( 𝑘 = 𝐾 → if ( ( 𝑄 ‘ 𝑘 ) = 𝐿 , 𝐴 , 𝐵 ) = if ( ( 𝑄 ‘ 𝐾 ) = 𝐿 , 𝐴 , 𝐵 ) )
7 id ⊢ ( 𝑘 = 𝐾 → 𝑘 = 𝐾 )
8 7 4 oveq12d ⊢ ( 𝑘 = 𝐾 → ( 𝑘 𝑀 ( 𝑄 ‘ 𝑘 ) ) = ( 𝐾 𝑀 ( 𝑄 ‘ 𝐾 ) ) )
9 3 6 8 ifbieq12d ⊢ ( 𝑘 = 𝐾 → if ( 𝑘 = 𝐾 , if ( ( 𝑄 ‘ 𝑘 ) = 𝐿 , 𝐴 , 𝐵 ) , ( 𝑘 𝑀 ( 𝑄 ‘ 𝑘 ) ) ) = if ( 𝐾 = 𝐾 , if ( ( 𝑄 ‘ 𝐾 ) = 𝐿 , 𝐴 , 𝐵 ) , ( 𝐾 𝑀 ( 𝑄 ‘ 𝐾 ) ) ) )
10 9 eqeq1d ⊢ ( 𝑘 = 𝐾 → ( if ( 𝑘 = 𝐾 , if ( ( 𝑄 ‘ 𝑘 ) = 𝐿 , 𝐴 , 𝐵 ) , ( 𝑘 𝑀 ( 𝑄 ‘ 𝑘 ) ) ) = 𝐵 ↔ if ( 𝐾 = 𝐾 , if ( ( 𝑄 ‘ 𝐾 ) = 𝐿 , 𝐴 , 𝐵 ) , ( 𝐾 𝑀 ( 𝑄 ‘ 𝐾 ) ) ) = 𝐵 ) )
11 10 adantl ⊢ ( ( ( ( 𝐾 ∈ 𝑁 ∧ 𝐿 ∈ 𝑁 ) ∧ 𝑄 ∈ ( 𝑃 ∖ { 𝑞 ∈ 𝑃 ∣ ( 𝑞 ‘ 𝐾 ) = 𝐿 } ) ) ∧ 𝑘 = 𝐾 ) → ( if ( 𝑘 = 𝐾 , if ( ( 𝑄 ‘ 𝑘 ) = 𝐿 , 𝐴 , 𝐵 ) , ( 𝑘 𝑀 ( 𝑄 ‘ 𝑘 ) ) ) = 𝐵 ↔ if ( 𝐾 = 𝐾 , if ( ( 𝑄 ‘ 𝐾 ) = 𝐿 , 𝐴 , 𝐵 ) , ( 𝐾 𝑀 ( 𝑄 ‘ 𝐾 ) ) ) = 𝐵 ) )
12 eqidd ⊢ ( ( ( 𝐾 ∈ 𝑁 ∧ 𝐿 ∈ 𝑁 ) ∧ 𝑄 ∈ ( 𝑃 ∖ { 𝑞 ∈ 𝑃 ∣ ( 𝑞 ‘ 𝐾 ) = 𝐿 } ) ) → 𝐾 = 𝐾 )
13 12 iftrued ⊢ ( ( ( 𝐾 ∈ 𝑁 ∧ 𝐿 ∈ 𝑁 ) ∧ 𝑄 ∈ ( 𝑃 ∖ { 𝑞 ∈ 𝑃 ∣ ( 𝑞 ‘ 𝐾 ) = 𝐿 } ) ) → if ( 𝐾 = 𝐾 , if ( ( 𝑄 ‘ 𝐾 ) = 𝐿 , 𝐴 , 𝐵 ) , ( 𝐾 𝑀 ( 𝑄 ‘ 𝐾 ) ) ) = if ( ( 𝑄 ‘ 𝐾 ) = 𝐿 , 𝐴 , 𝐵 ) )
14 eldif ⊢ ( 𝑄 ∈ ( 𝑃 ∖ { 𝑞 ∈ 𝑃 ∣ ( 𝑞 ‘ 𝐾 ) = 𝐿 } ) ↔ ( 𝑄 ∈ 𝑃 ∧ ¬ 𝑄 ∈ { 𝑞 ∈ 𝑃 ∣ ( 𝑞 ‘ 𝐾 ) = 𝐿 } ) )
15 ianor ⊢ ( ¬ ( 𝑄 ∈ 𝑃 ∧ ( 𝑄 ‘ 𝐾 ) = 𝐿 ) ↔ ( ¬ 𝑄 ∈ 𝑃 ∨ ¬ ( 𝑄 ‘ 𝐾 ) = 𝐿 ) )
16 fveq1 ⊢ ( 𝑞 = 𝑄 → ( 𝑞 ‘ 𝐾 ) = ( 𝑄 ‘ 𝐾 ) )
17 16 eqeq1d ⊢ ( 𝑞 = 𝑄 → ( ( 𝑞 ‘ 𝐾 ) = 𝐿 ↔ ( 𝑄 ‘ 𝐾 ) = 𝐿 ) )
18 17 elrab ⊢ ( 𝑄 ∈ { 𝑞 ∈ 𝑃 ∣ ( 𝑞 ‘ 𝐾 ) = 𝐿 } ↔ ( 𝑄 ∈ 𝑃 ∧ ( 𝑄 ‘ 𝐾 ) = 𝐿 ) )
19 15 18 xchnxbir ⊢ ( ¬ 𝑄 ∈ { 𝑞 ∈ 𝑃 ∣ ( 𝑞 ‘ 𝐾 ) = 𝐿 } ↔ ( ¬ 𝑄 ∈ 𝑃 ∨ ¬ ( 𝑄 ‘ 𝐾 ) = 𝐿 ) )
20 pm2.21 ⊢ ( ¬ 𝑄 ∈ 𝑃 → ( 𝑄 ∈ 𝑃 → ¬ ( 𝑄 ‘ 𝐾 ) = 𝐿 ) )
21 ax-1 ⊢ ( ¬ ( 𝑄 ‘ 𝐾 ) = 𝐿 → ( 𝑄 ∈ 𝑃 → ¬ ( 𝑄 ‘ 𝐾 ) = 𝐿 ) )
22 20 21 jaoi ⊢ ( ( ¬ 𝑄 ∈ 𝑃 ∨ ¬ ( 𝑄 ‘ 𝐾 ) = 𝐿 ) → ( 𝑄 ∈ 𝑃 → ¬ ( 𝑄 ‘ 𝐾 ) = 𝐿 ) )
23 19 22 sylbi ⊢ ( ¬ 𝑄 ∈ { 𝑞 ∈ 𝑃 ∣ ( 𝑞 ‘ 𝐾 ) = 𝐿 } → ( 𝑄 ∈ 𝑃 → ¬ ( 𝑄 ‘ 𝐾 ) = 𝐿 ) )
24 23 impcom ⊢ ( ( 𝑄 ∈ 𝑃 ∧ ¬ 𝑄 ∈ { 𝑞 ∈ 𝑃 ∣ ( 𝑞 ‘ 𝐾 ) = 𝐿 } ) → ¬ ( 𝑄 ‘ 𝐾 ) = 𝐿 )
25 14 24 sylbi ⊢ ( 𝑄 ∈ ( 𝑃 ∖ { 𝑞 ∈ 𝑃 ∣ ( 𝑞 ‘ 𝐾 ) = 𝐿 } ) → ¬ ( 𝑄 ‘ 𝐾 ) = 𝐿 )
26 25 adantl ⊢ ( ( ( 𝐾 ∈ 𝑁 ∧ 𝐿 ∈ 𝑁 ) ∧ 𝑄 ∈ ( 𝑃 ∖ { 𝑞 ∈ 𝑃 ∣ ( 𝑞 ‘ 𝐾 ) = 𝐿 } ) ) → ¬ ( 𝑄 ‘ 𝐾 ) = 𝐿 )
27 26 iffalsed ⊢ ( ( ( 𝐾 ∈ 𝑁 ∧ 𝐿 ∈ 𝑁 ) ∧ 𝑄 ∈ ( 𝑃 ∖ { 𝑞 ∈ 𝑃 ∣ ( 𝑞 ‘ 𝐾 ) = 𝐿 } ) ) → if ( ( 𝑄 ‘ 𝐾 ) = 𝐿 , 𝐴 , 𝐵 ) = 𝐵 )
28 13 27 eqtrd ⊢ ( ( ( 𝐾 ∈ 𝑁 ∧ 𝐿 ∈ 𝑁 ) ∧ 𝑄 ∈ ( 𝑃 ∖ { 𝑞 ∈ 𝑃 ∣ ( 𝑞 ‘ 𝐾 ) = 𝐿 } ) ) → if ( 𝐾 = 𝐾 , if ( ( 𝑄 ‘ 𝐾 ) = 𝐿 , 𝐴 , 𝐵 ) , ( 𝐾 𝑀 ( 𝑄 ‘ 𝐾 ) ) ) = 𝐵 )
29 2 11 28 rspcedvd ⊢ ( ( ( 𝐾 ∈ 𝑁 ∧ 𝐿 ∈ 𝑁 ) ∧ 𝑄 ∈ ( 𝑃 ∖ { 𝑞 ∈ 𝑃 ∣ ( 𝑞 ‘ 𝐾 ) = 𝐿 } ) ) → ∃ 𝑘 ∈ 𝑁 if ( 𝑘 = 𝐾 , if ( ( 𝑄 ‘ 𝑘 ) = 𝐿 , 𝐴 , 𝐵 ) , ( 𝑘 𝑀 ( 𝑄 ‘ 𝑘 ) ) ) = 𝐵 )
30 29 ex ⊢ ( ( 𝐾 ∈ 𝑁 ∧ 𝐿 ∈ 𝑁 ) → ( 𝑄 ∈ ( 𝑃 ∖ { 𝑞 ∈ 𝑃 ∣ ( 𝑞 ‘ 𝐾 ) = 𝐿 } ) → ∃ 𝑘 ∈ 𝑁 if ( 𝑘 = 𝐾 , if ( ( 𝑄 ‘ 𝑘 ) = 𝐿 , 𝐴 , 𝐵 ) , ( 𝑘 𝑀 ( 𝑄 ‘ 𝑘 ) ) ) = 𝐵 ) )