Metamath Proof Explorer


Theorem symgmov1

Description: For a permutation of a set, each element of the set replaces an(other) element of the set. (Contributed by AV, 2-Jan-2019)

Ref Expression
Hypothesis symgmov1.p ⊢ 𝑃 = ( Base ‘ ( SymGrp ‘ 𝑁 ) )
Assertion symgmov1 ( 𝑄 ∈ 𝑃 → ∀ 𝑛 ∈ 𝑁 ∃ 𝑘 ∈ 𝑁 ( 𝑄 ‘ 𝑛 ) = 𝑘 )

Proof

Step Hyp Ref Expression
1 symgmov1.p ⊢ 𝑃 = ( Base ‘ ( SymGrp ‘ 𝑁 ) )
2 eqid ⊢ ( SymGrp ‘ 𝑁 ) = ( SymGrp ‘ 𝑁 )
3 2 1 symgfv ⊢ ( ( 𝑄 ∈ 𝑃 ∧ 𝑛 ∈ 𝑁 ) → ( 𝑄 ‘ 𝑛 ) ∈ 𝑁 )
4 clel5 ⊢ ( ( 𝑄 ‘ 𝑛 ) ∈ 𝑁 ↔ ∃ 𝑘 ∈ 𝑁 ( 𝑄 ‘ 𝑛 ) = 𝑘 )
5 3 4 sylib ⊢ ( ( 𝑄 ∈ 𝑃 ∧ 𝑛 ∈ 𝑁 ) → ∃ 𝑘 ∈ 𝑁 ( 𝑄 ‘ 𝑛 ) = 𝑘 )
6 5 ralrimiva ⊢ ( 𝑄 ∈ 𝑃 → ∀ 𝑛 ∈ 𝑁 ∃ 𝑘 ∈ 𝑁 ( 𝑄 ‘ 𝑛 ) = 𝑘 )