Metamath Proof Explorer


Theorem tpos0

Description: Transposition of the empty set. (Contributed by NM, 10-Sep-2015)

Ref Expression
Assertion tpos0 tpos ∅ = ∅

Proof

Step Hyp Ref Expression
1 rel0 Rel ∅
2 eqid ∅ = ∅
3 fn0 ( ∅ Fn ∅ ↔ ∅ = ∅ )
4 2 3 mpbir ∅ Fn ∅
5 tposfn2 ( Rel ∅ → ( ∅ Fn ∅ → tpos ∅ Fn ∅ ) )
6 1 4 5 mp2 tpos ∅ Fn
7 cnv0 ∅ = ∅
8 7 fneq2i ( tpos ∅ Fn ∅ ↔ tpos ∅ Fn ∅ )
9 6 8 mpbi tpos ∅ Fn ∅
10 fn0 ( tpos ∅ Fn ∅ ↔ tpos ∅ = ∅ )
11 9 10 mpbi tpos ∅ = ∅