Metamath Proof Explorer


Theorem tposeq

Description: Equality theorem for transposition. (Contributed by Mario Carneiro, 10-Sep-2015)

Ref Expression
Assertion tposeq ( 𝐹 = 𝐺 → tpos 𝐹 = tpos 𝐺 )

Proof

Step Hyp Ref Expression
1 eqimss ⊢ ( 𝐹 = 𝐺 → 𝐹 ⊆ 𝐺 )
2 tposss ⊢ ( 𝐹 ⊆ 𝐺 → tpos 𝐹 ⊆ tpos 𝐺 )
3 1 2 syl ⊢ ( 𝐹 = 𝐺 → tpos 𝐹 ⊆ tpos 𝐺 )
4 eqimss2 ⊢ ( 𝐹 = 𝐺 → 𝐺 ⊆ 𝐹 )
5 tposss ⊢ ( 𝐺 ⊆ 𝐹 → tpos 𝐺 ⊆ tpos 𝐹 )
6 4 5 syl ⊢ ( 𝐹 = 𝐺 → tpos 𝐺 ⊆ tpos 𝐹 )
7 3 6 eqssd ⊢ ( 𝐹 = 𝐺 → tpos 𝐹 = tpos 𝐺 )