Metamath Proof Explorer


Theorem tpssd

Description: Deduction version of tpssi : An unordered triple of elements of a class is a subset of that class. (Contributed by Thierry Arnoux, 2-Nov-2025)

Ref Expression
Hypotheses tpssd.1 ⊢ ( 𝜑 → 𝐴 ∈ 𝐷 )
tpssd.2 ⊢ ( 𝜑 → 𝐵 ∈ 𝐷 )
tpssd.3 ⊢ ( 𝜑 → 𝐶 ∈ 𝐷 )
Assertion tpssd ( 𝜑 → { 𝐴 , 𝐵 , 𝐶 } ⊆ 𝐷 )

Proof

Step Hyp Ref Expression
1 tpssd.1 ⊢ ( 𝜑 → 𝐴 ∈ 𝐷 )
2 tpssd.2 ⊢ ( 𝜑 → 𝐵 ∈ 𝐷 )
3 tpssd.3 ⊢ ( 𝜑 → 𝐶 ∈ 𝐷 )
4 tpssi ⊢ ( ( 𝐴 ∈ 𝐷 ∧ 𝐵 ∈ 𝐷 ∧ 𝐶 ∈ 𝐷 ) → { 𝐴 , 𝐵 , 𝐶 } ⊆ 𝐷 )
5 1 2 3 4 syl3anc ⊢ ( 𝜑 → { 𝐴 , 𝐵 , 𝐶 } ⊆ 𝐷 )