Metamath Proof Explorer


Theorem trlcocnv

Description: Swap the arguments of the trace of a composition with converse. (Contributed by NM, 1-Jul-2013)

Ref Expression
Hypotheses trlcocnv.h ⊢ 𝐻 = ( LHyp ‘ 𝐾 )
trlcocnv.t ⊢ 𝑇 = ( ( LTrn ‘ 𝐾 ) ‘ 𝑊 )
trlcocnv.r ⊢ 𝑅 = ( ( trL ‘ 𝐾 ) ‘ 𝑊 )
Assertion trlcocnv ( ( ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) ∧ 𝐹 ∈ 𝑇 ∧ 𝐺 ∈ 𝑇 ) → ( 𝑅 ‘ ( 𝐹 ∘ ◡ 𝐺 ) ) = ( 𝑅 ‘ ( 𝐺 ∘ ◡ 𝐹 ) ) )

Proof

Step Hyp Ref Expression
1 trlcocnv.h ⊢ 𝐻 = ( LHyp ‘ 𝐾 )
2 trlcocnv.t ⊢ 𝑇 = ( ( LTrn ‘ 𝐾 ) ‘ 𝑊 )
3 trlcocnv.r ⊢ 𝑅 = ( ( trL ‘ 𝐾 ) ‘ 𝑊 )
4 simp1 ⊢ ( ( ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) ∧ 𝐹 ∈ 𝑇 ∧ 𝐺 ∈ 𝑇 ) → ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) )
5 1 2 ltrncnv ⊢ ( ( ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) ∧ 𝐺 ∈ 𝑇 ) → ◡ 𝐺 ∈ 𝑇 )
6 5 3adant2 ⊢ ( ( ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) ∧ 𝐹 ∈ 𝑇 ∧ 𝐺 ∈ 𝑇 ) → ◡ 𝐺 ∈ 𝑇 )
7 1 2 ltrnco ⊢ ( ( ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) ∧ 𝐹 ∈ 𝑇 ∧ ◡ 𝐺 ∈ 𝑇 ) → ( 𝐹 ∘ ◡ 𝐺 ) ∈ 𝑇 )
8 6 7 syld3an3 ⊢ ( ( ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) ∧ 𝐹 ∈ 𝑇 ∧ 𝐺 ∈ 𝑇 ) → ( 𝐹 ∘ ◡ 𝐺 ) ∈ 𝑇 )
9 1 2 3 trlcnv ⊢ ( ( ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) ∧ ( 𝐹 ∘ ◡ 𝐺 ) ∈ 𝑇 ) → ( 𝑅 ‘ ◡ ( 𝐹 ∘ ◡ 𝐺 ) ) = ( 𝑅 ‘ ( 𝐹 ∘ ◡ 𝐺 ) ) )
10 4 8 9 syl2anc ⊢ ( ( ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) ∧ 𝐹 ∈ 𝑇 ∧ 𝐺 ∈ 𝑇 ) → ( 𝑅 ‘ ◡ ( 𝐹 ∘ ◡ 𝐺 ) ) = ( 𝑅 ‘ ( 𝐹 ∘ ◡ 𝐺 ) ) )
11 cnvco ⊢ ◡ ( 𝐹 ∘ ◡ 𝐺 ) = ( ◡ ◡ 𝐺 ∘ ◡ 𝐹 )
12 cocnvcnv1 ⊢ ( ◡ ◡ 𝐺 ∘ ◡ 𝐹 ) = ( 𝐺 ∘ ◡ 𝐹 )
13 11 12 eqtri ⊢ ◡ ( 𝐹 ∘ ◡ 𝐺 ) = ( 𝐺 ∘ ◡ 𝐹 )
14 13 fveq2i ⊢ ( 𝑅 ‘ ◡ ( 𝐹 ∘ ◡ 𝐺 ) ) = ( 𝑅 ‘ ( 𝐺 ∘ ◡ 𝐹 ) )
15 10 14 eqtr3di ⊢ ( ( ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) ∧ 𝐹 ∈ 𝑇 ∧ 𝐺 ∈ 𝑇 ) → ( 𝑅 ‘ ( 𝐹 ∘ ◡ 𝐺 ) ) = ( 𝑅 ‘ ( 𝐺 ∘ ◡ 𝐹 ) ) )