Metamath Proof Explorer
Description: In a hypergraph, a set is an edge iff it is an indexed edge.
(Contributed by AV, 17-Oct-2020)
|
|
Ref |
Expression |
|
Hypothesis |
uhgredgiedgb.i |
⊢ 𝐼 = ( iEdg ‘ 𝐺 ) |
|
Assertion |
uhgredgiedgb |
⊢ ( 𝐺 ∈ UHGraph → ( 𝐸 ∈ ( Edg ‘ 𝐺 ) ↔ ∃ 𝑥 ∈ dom 𝐼 𝐸 = ( 𝐼 ‘ 𝑥 ) ) ) |
Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
uhgredgiedgb.i |
⊢ 𝐼 = ( iEdg ‘ 𝐺 ) |
2 |
1
|
uhgrfun |
⊢ ( 𝐺 ∈ UHGraph → Fun 𝐼 ) |
3 |
1
|
edgiedgb |
⊢ ( Fun 𝐼 → ( 𝐸 ∈ ( Edg ‘ 𝐺 ) ↔ ∃ 𝑥 ∈ dom 𝐼 𝐸 = ( 𝐼 ‘ 𝑥 ) ) ) |
4 |
2 3
|
syl |
⊢ ( 𝐺 ∈ UHGraph → ( 𝐸 ∈ ( Edg ‘ 𝐺 ) ↔ ∃ 𝑥 ∈ dom 𝐼 𝐸 = ( 𝐼 ‘ 𝑥 ) ) ) |