Metamath Proof Explorer


Theorem undisj2

Description: The union of disjoint classes is disjoint. (Contributed by NM, 13-Sep-2004)

Ref Expression
Assertion undisj2 ( ( ( 𝐴𝐵 ) = ∅ ∧ ( 𝐴𝐶 ) = ∅ ) ↔ ( 𝐴 ∩ ( 𝐵𝐶 ) ) = ∅ )

Proof

Step Hyp Ref Expression
1 un00 ( ( ( 𝐴𝐵 ) = ∅ ∧ ( 𝐴𝐶 ) = ∅ ) ↔ ( ( 𝐴𝐵 ) ∪ ( 𝐴𝐶 ) ) = ∅ )
2 indi ( 𝐴 ∩ ( 𝐵𝐶 ) ) = ( ( 𝐴𝐵 ) ∪ ( 𝐴𝐶 ) )
3 2 eqeq1i ( ( 𝐴 ∩ ( 𝐵𝐶 ) ) = ∅ ↔ ( ( 𝐴𝐵 ) ∪ ( 𝐴𝐶 ) ) = ∅ )
4 1 3 bitr4i ( ( ( 𝐴𝐵 ) = ∅ ∧ ( 𝐴𝐶 ) = ∅ ) ↔ ( 𝐴 ∩ ( 𝐵𝐶 ) ) = ∅ )