Description: In a pseudograph with two vertices and an edge connecting these two vertices, to go from one vertex to the other vertex via this edge is a path from one of these vertices to the other vertex. The two vertices need not be distinct (in the case of a loop) - in this case, however, the path is not a simple path. (Contributed by AV, 22-Jan-2021)
Ref | Expression | ||
---|---|---|---|
Hypotheses | upgr1wlkd.p | ⊢ 𝑃 = 〈“ 𝑋 𝑌 ”〉 | |
upgr1wlkd.f | ⊢ 𝐹 = 〈“ 𝐽 ”〉 | ||
upgr1wlkd.x | ⊢ ( 𝜑 → 𝑋 ∈ ( Vtx ‘ 𝐺 ) ) | ||
upgr1wlkd.y | ⊢ ( 𝜑 → 𝑌 ∈ ( Vtx ‘ 𝐺 ) ) | ||
upgr1wlkd.j | ⊢ ( 𝜑 → ( ( iEdg ‘ 𝐺 ) ‘ 𝐽 ) = { 𝑋 , 𝑌 } ) | ||
upgr1wlkd.g | ⊢ ( 𝜑 → 𝐺 ∈ UPGraph ) | ||
Assertion | upgr1pthond | ⊢ ( 𝜑 → 𝐹 ( 𝑋 ( PathsOn ‘ 𝐺 ) 𝑌 ) 𝑃 ) |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | upgr1wlkd.p | ⊢ 𝑃 = 〈“ 𝑋 𝑌 ”〉 | |
2 | upgr1wlkd.f | ⊢ 𝐹 = 〈“ 𝐽 ”〉 | |
3 | upgr1wlkd.x | ⊢ ( 𝜑 → 𝑋 ∈ ( Vtx ‘ 𝐺 ) ) | |
4 | upgr1wlkd.y | ⊢ ( 𝜑 → 𝑌 ∈ ( Vtx ‘ 𝐺 ) ) | |
5 | upgr1wlkd.j | ⊢ ( 𝜑 → ( ( iEdg ‘ 𝐺 ) ‘ 𝐽 ) = { 𝑋 , 𝑌 } ) | |
6 | upgr1wlkd.g | ⊢ ( 𝜑 → 𝐺 ∈ UPGraph ) | |
7 | 1 2 3 4 5 | upgr1wlkdlem1 | ⊢ ( ( 𝜑 ∧ 𝑋 = 𝑌 ) → ( ( iEdg ‘ 𝐺 ) ‘ 𝐽 ) = { 𝑋 } ) |
8 | 1 2 3 4 5 | upgr1wlkdlem2 | ⊢ ( ( 𝜑 ∧ 𝑋 ≠ 𝑌 ) → { 𝑋 , 𝑌 } ⊆ ( ( iEdg ‘ 𝐺 ) ‘ 𝐽 ) ) |
9 | eqid | ⊢ ( Vtx ‘ 𝐺 ) = ( Vtx ‘ 𝐺 ) | |
10 | eqid | ⊢ ( iEdg ‘ 𝐺 ) = ( iEdg ‘ 𝐺 ) | |
11 | 1 2 3 4 7 8 9 10 | 1pthond | ⊢ ( 𝜑 → 𝐹 ( 𝑋 ( PathsOn ‘ 𝐺 ) 𝑌 ) 𝑃 ) |