Metamath Proof Explorer


Theorem upgrres1lem2

Description: Lemma 2 for upgrres1 . (Contributed by AV, 7-Nov-2020)

Ref Expression
Hypotheses upgrres1.v ⊢ 𝑉 = ( Vtx ‘ 𝐺 )
upgrres1.e ⊢ 𝐸 = ( Edg ‘ 𝐺 )
upgrres1.f ⊢ 𝐹 = { 𝑒 ∈ 𝐸 ∣ 𝑁 ∉ 𝑒 }
upgrres1.s ⊢ 𝑆 = ⟨ ( 𝑉 ∖ { 𝑁 } ) , ( I ↾ 𝐹 ) ⟩
Assertion upgrres1lem2 ( Vtx ‘ 𝑆 ) = ( 𝑉 ∖ { 𝑁 } )

Proof

Step Hyp Ref Expression
1 upgrres1.v ⊢ 𝑉 = ( Vtx ‘ 𝐺 )
2 upgrres1.e ⊢ 𝐸 = ( Edg ‘ 𝐺 )
3 upgrres1.f ⊢ 𝐹 = { 𝑒 ∈ 𝐸 ∣ 𝑁 ∉ 𝑒 }
4 upgrres1.s ⊢ 𝑆 = ⟨ ( 𝑉 ∖ { 𝑁 } ) , ( I ↾ 𝐹 ) ⟩
5 4 fveq2i ⊢ ( Vtx ‘ 𝑆 ) = ( Vtx ‘ ⟨ ( 𝑉 ∖ { 𝑁 } ) , ( I ↾ 𝐹 ) ⟩ )
6 1 2 3 upgrres1lem1 ⊢ ( ( 𝑉 ∖ { 𝑁 } ) ∈ V ∧ ( I ↾ 𝐹 ) ∈ V )
7 opvtxfv ⊢ ( ( ( 𝑉 ∖ { 𝑁 } ) ∈ V ∧ ( I ↾ 𝐹 ) ∈ V ) → ( Vtx ‘ ⟨ ( 𝑉 ∖ { 𝑁 } ) , ( I ↾ 𝐹 ) ⟩ ) = ( 𝑉 ∖ { 𝑁 } ) )
8 6 7 ax-mp ⊢ ( Vtx ‘ ⟨ ( 𝑉 ∖ { 𝑁 } ) , ( I ↾ 𝐹 ) ⟩ ) = ( 𝑉 ∖ { 𝑁 } )
9 5 8 eqtri ⊢ ( Vtx ‘ 𝑆 ) = ( 𝑉 ∖ { 𝑁 } )