Metamath Proof Explorer


Theorem upgrwlkedg

Description: The edges of a walk in a pseudograph join exactly the two corresponding adjacent vertices in the walk. (Contributed by AV, 27-Feb-2021)

Ref Expression
Hypothesis upgrwlkedg.i 𝐼 = ( iEdg ‘ 𝐺 )
Assertion upgrwlkedg ( ( 𝐺 ∈ UPGraph ∧ 𝐹 ( Walks ‘ 𝐺 ) 𝑃 ) → ∀ 𝑘 ∈ ( 0 ..^ ( ♯ ‘ 𝐹 ) ) ( 𝐼 ‘ ( 𝐹𝑘 ) ) = { ( 𝑃𝑘 ) , ( 𝑃 ‘ ( 𝑘 + 1 ) ) } )

Proof

Step Hyp Ref Expression
1 upgrwlkedg.i 𝐼 = ( iEdg ‘ 𝐺 )
2 eqid ( Vtx ‘ 𝐺 ) = ( Vtx ‘ 𝐺 )
3 2 1 upgriswlk ( 𝐺 ∈ UPGraph → ( 𝐹 ( Walks ‘ 𝐺 ) 𝑃 ↔ ( 𝐹 ∈ Word dom 𝐼𝑃 : ( 0 ... ( ♯ ‘ 𝐹 ) ) ⟶ ( Vtx ‘ 𝐺 ) ∧ ∀ 𝑘 ∈ ( 0 ..^ ( ♯ ‘ 𝐹 ) ) ( 𝐼 ‘ ( 𝐹𝑘 ) ) = { ( 𝑃𝑘 ) , ( 𝑃 ‘ ( 𝑘 + 1 ) ) } ) ) )
4 simp3 ( ( 𝐹 ∈ Word dom 𝐼𝑃 : ( 0 ... ( ♯ ‘ 𝐹 ) ) ⟶ ( Vtx ‘ 𝐺 ) ∧ ∀ 𝑘 ∈ ( 0 ..^ ( ♯ ‘ 𝐹 ) ) ( 𝐼 ‘ ( 𝐹𝑘 ) ) = { ( 𝑃𝑘 ) , ( 𝑃 ‘ ( 𝑘 + 1 ) ) } ) → ∀ 𝑘 ∈ ( 0 ..^ ( ♯ ‘ 𝐹 ) ) ( 𝐼 ‘ ( 𝐹𝑘 ) ) = { ( 𝑃𝑘 ) , ( 𝑃 ‘ ( 𝑘 + 1 ) ) } )
5 3 4 syl6bi ( 𝐺 ∈ UPGraph → ( 𝐹 ( Walks ‘ 𝐺 ) 𝑃 → ∀ 𝑘 ∈ ( 0 ..^ ( ♯ ‘ 𝐹 ) ) ( 𝐼 ‘ ( 𝐹𝑘 ) ) = { ( 𝑃𝑘 ) , ( 𝑃 ‘ ( 𝑘 + 1 ) ) } ) )
6 5 imp ( ( 𝐺 ∈ UPGraph ∧ 𝐹 ( Walks ‘ 𝐺 ) 𝑃 ) → ∀ 𝑘 ∈ ( 0 ..^ ( ♯ ‘ 𝐹 ) ) ( 𝐼 ‘ ( 𝐹𝑘 ) ) = { ( 𝑃𝑘 ) , ( 𝑃 ‘ ( 𝑘 + 1 ) ) } )