Metamath Proof Explorer


Theorem usgr2pthspth

Description: In a simple graph, any path of length 2 is a simple path. (Contributed by Alexander van der Vekens, 25-Jan-2018) (Revised by AV, 5-Jun-2021)

Ref Expression
Assertion usgr2pthspth ( ( 𝐺 ∈ USGraph ∧ ( ♯ ‘ 𝐹 ) = 2 ) → ( 𝐹 ( Paths ‘ 𝐺 ) 𝑃 ↔ 𝐹 ( SPaths ‘ 𝐺 ) 𝑃 ) )

Proof

Step Hyp Ref Expression
1 pthistrl ⊢ ( 𝐹 ( Paths ‘ 𝐺 ) 𝑃 → 𝐹 ( Trails ‘ 𝐺 ) 𝑃 )
2 usgr2trlspth ⊢ ( ( 𝐺 ∈ USGraph ∧ ( ♯ ‘ 𝐹 ) = 2 ) → ( 𝐹 ( Trails ‘ 𝐺 ) 𝑃 ↔ 𝐹 ( SPaths ‘ 𝐺 ) 𝑃 ) )
3 1 2 imbitrid ⊢ ( ( 𝐺 ∈ USGraph ∧ ( ♯ ‘ 𝐹 ) = 2 ) → ( 𝐹 ( Paths ‘ 𝐺 ) 𝑃 → 𝐹 ( SPaths ‘ 𝐺 ) 𝑃 ) )
4 spthispth ⊢ ( 𝐹 ( SPaths ‘ 𝐺 ) 𝑃 → 𝐹 ( Paths ‘ 𝐺 ) 𝑃 )
5 3 4 impbid1 ⊢ ( ( 𝐺 ∈ USGraph ∧ ( ♯ ‘ 𝐹 ) = 2 ) → ( 𝐹 ( Paths ‘ 𝐺 ) 𝑃 ↔ 𝐹 ( SPaths ‘ 𝐺 ) 𝑃 ) )