Metamath Proof Explorer


Theorem uzind4s2

Description: Induction on the upper set of integers that starts at an integer M , using explicit substitution. The hypotheses are the basis and the induction step. Use this instead of uzind4s when j and k must be distinct in [. ( k + 1 ) / j ]. ph . (Contributed by NM, 16-Nov-2005)

Ref Expression
Hypotheses uzind4s2.1 ( 𝑀 ∈ ℤ → [ 𝑀 / 𝑗 ] 𝜑 )
uzind4s2.2 ( 𝑘 ∈ ( ℤ𝑀 ) → ( [ 𝑘 / 𝑗 ] 𝜑[ ( 𝑘 + 1 ) / 𝑗 ] 𝜑 ) )
Assertion uzind4s2 ( 𝑁 ∈ ( ℤ𝑀 ) → [ 𝑁 / 𝑗 ] 𝜑 )

Proof

Step Hyp Ref Expression
1 uzind4s2.1 ( 𝑀 ∈ ℤ → [ 𝑀 / 𝑗 ] 𝜑 )
2 uzind4s2.2 ( 𝑘 ∈ ( ℤ𝑀 ) → ( [ 𝑘 / 𝑗 ] 𝜑[ ( 𝑘 + 1 ) / 𝑗 ] 𝜑 ) )
3 dfsbcq ( 𝑚 = 𝑀 → ( [ 𝑚 / 𝑗 ] 𝜑[ 𝑀 / 𝑗 ] 𝜑 ) )
4 dfsbcq ( 𝑚 = 𝑛 → ( [ 𝑚 / 𝑗 ] 𝜑[ 𝑛 / 𝑗 ] 𝜑 ) )
5 dfsbcq ( 𝑚 = ( 𝑛 + 1 ) → ( [ 𝑚 / 𝑗 ] 𝜑[ ( 𝑛 + 1 ) / 𝑗 ] 𝜑 ) )
6 dfsbcq ( 𝑚 = 𝑁 → ( [ 𝑚 / 𝑗 ] 𝜑[ 𝑁 / 𝑗 ] 𝜑 ) )
7 dfsbcq ( 𝑘 = 𝑛 → ( [ 𝑘 / 𝑗 ] 𝜑[ 𝑛 / 𝑗 ] 𝜑 ) )
8 oveq1 ( 𝑘 = 𝑛 → ( 𝑘 + 1 ) = ( 𝑛 + 1 ) )
9 8 sbceq1d ( 𝑘 = 𝑛 → ( [ ( 𝑘 + 1 ) / 𝑗 ] 𝜑[ ( 𝑛 + 1 ) / 𝑗 ] 𝜑 ) )
10 7 9 imbi12d ( 𝑘 = 𝑛 → ( ( [ 𝑘 / 𝑗 ] 𝜑[ ( 𝑘 + 1 ) / 𝑗 ] 𝜑 ) ↔ ( [ 𝑛 / 𝑗 ] 𝜑[ ( 𝑛 + 1 ) / 𝑗 ] 𝜑 ) ) )
11 10 2 vtoclga ( 𝑛 ∈ ( ℤ𝑀 ) → ( [ 𝑛 / 𝑗 ] 𝜑[ ( 𝑛 + 1 ) / 𝑗 ] 𝜑 ) )
12 3 4 5 6 1 11 uzind4 ( 𝑁 ∈ ( ℤ𝑀 ) → [ 𝑁 / 𝑗 ] 𝜑 )