Metamath Proof Explorer


Theorem wwlksnon0

Description: Sufficient conditions for a set of walks of a fixed length between two vertices to be empty. (Contributed by AV, 15-May-2021) (Proof shortened by AV, 21-May-2021)

Ref Expression
Hypothesis wwlksnon0.v 𝑉 = ( Vtx ‘ 𝐺 )
Assertion wwlksnon0 ( ¬ ( ( 𝑁 ∈ ℕ0𝐺 ∈ V ) ∧ ( 𝐴𝑉𝐵𝑉 ) ) → ( 𝐴 ( 𝑁 WWalksNOn 𝐺 ) 𝐵 ) = ∅ )

Proof

Step Hyp Ref Expression
1 wwlksnon0.v 𝑉 = ( Vtx ‘ 𝐺 )
2 df-wwlksnon WWalksNOn = ( 𝑛 ∈ ℕ0 , 𝑔 ∈ V ↦ ( 𝑎 ∈ ( Vtx ‘ 𝑔 ) , 𝑏 ∈ ( Vtx ‘ 𝑔 ) ↦ { 𝑤 ∈ ( 𝑛 WWalksN 𝑔 ) ∣ ( ( 𝑤 ‘ 0 ) = 𝑎 ∧ ( 𝑤𝑛 ) = 𝑏 ) } ) )
3 1 wwlksnon ( ( 𝑁 ∈ ℕ0𝐺 ∈ V ) → ( 𝑁 WWalksNOn 𝐺 ) = ( 𝑎𝑉 , 𝑏𝑉 ↦ { 𝑤 ∈ ( 𝑁 WWalksN 𝐺 ) ∣ ( ( 𝑤 ‘ 0 ) = 𝑎 ∧ ( 𝑤𝑁 ) = 𝑏 ) } ) )
4 2 3 2mpo0 ( ¬ ( ( 𝑁 ∈ ℕ0𝐺 ∈ V ) ∧ ( 𝐴𝑉𝐵𝑉 ) ) → ( 𝐴 ( 𝑁 WWalksNOn 𝐺 ) 𝐵 ) = ∅ )