Metamath Proof Explorer
Description: Equality of two extended numbers with -e in front of them.
(Contributed by Glauco Siliprandi, 2-Jan-2022)
|
|
Ref |
Expression |
|
Hypothesis |
xnegeqd.1 |
⊢ ( 𝜑 → 𝐴 = 𝐵 ) |
|
Assertion |
xnegeqd |
⊢ ( 𝜑 → -𝑒 𝐴 = -𝑒 𝐵 ) |
Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
xnegeqd.1 |
⊢ ( 𝜑 → 𝐴 = 𝐵 ) |
2 |
|
xnegeq |
⊢ ( 𝐴 = 𝐵 → -𝑒 𝐴 = -𝑒 𝐵 ) |
3 |
1 2
|
syl |
⊢ ( 𝜑 → -𝑒 𝐴 = -𝑒 𝐵 ) |