Metamath Proof Explorer


Theorem xorbi12d

Description: Equality property for exclusive disjunction. (Contributed by Mario Carneiro, 4-Sep-2016)

Ref Expression
Hypotheses xor12d.1 ⊢ ( 𝜑 → ( 𝜓 ↔ 𝜒 ) )
xor12d.2 ⊢ ( 𝜑 → ( 𝜃 ↔ 𝜏 ) )
Assertion xorbi12d ( 𝜑 → ( ( 𝜓 ⊻ 𝜃 ) ↔ ( 𝜒 ⊻ 𝜏 ) ) )

Proof

Step Hyp Ref Expression
1 xor12d.1 ⊢ ( 𝜑 → ( 𝜓 ↔ 𝜒 ) )
2 xor12d.2 ⊢ ( 𝜑 → ( 𝜃 ↔ 𝜏 ) )
3 1 2 bibi12d ⊢ ( 𝜑 → ( ( 𝜓 ↔ 𝜃 ) ↔ ( 𝜒 ↔ 𝜏 ) ) )
4 3 notbid ⊢ ( 𝜑 → ( ¬ ( 𝜓 ↔ 𝜃 ) ↔ ¬ ( 𝜒 ↔ 𝜏 ) ) )
5 df-xor ⊢ ( ( 𝜓 ⊻ 𝜃 ) ↔ ¬ ( 𝜓 ↔ 𝜃 ) )
6 df-xor ⊢ ( ( 𝜒 ⊻ 𝜏 ) ↔ ¬ ( 𝜒 ↔ 𝜏 ) )
7 4 5 6 3bitr4g ⊢ ( 𝜑 → ( ( 𝜓 ⊻ 𝜃 ) ↔ ( 𝜒 ⊻ 𝜏 ) ) )