Step |
Hyp |
Ref |
Expression |
1 |
|
xp11 |
⊢ ( ( 𝐴 ≠ ∅ ∧ 𝐶 ≠ ∅ ) → ( ( 𝐴 × 𝐶 ) = ( 𝐵 × 𝐶 ) ↔ ( 𝐴 = 𝐵 ∧ 𝐶 = 𝐶 ) ) ) |
2 |
|
eqid |
⊢ 𝐶 = 𝐶 |
3 |
2
|
biantru |
⊢ ( 𝐴 = 𝐵 ↔ ( 𝐴 = 𝐵 ∧ 𝐶 = 𝐶 ) ) |
4 |
1 3
|
bitr4di |
⊢ ( ( 𝐴 ≠ ∅ ∧ 𝐶 ≠ ∅ ) → ( ( 𝐴 × 𝐶 ) = ( 𝐵 × 𝐶 ) ↔ 𝐴 = 𝐵 ) ) |
5 |
|
nne |
⊢ ( ¬ 𝐴 ≠ ∅ ↔ 𝐴 = ∅ ) |
6 |
|
simpl |
⊢ ( ( 𝐴 = ∅ ∧ 𝐶 ≠ ∅ ) → 𝐴 = ∅ ) |
7 |
|
xpeq1 |
⊢ ( 𝐴 = ∅ → ( 𝐴 × 𝐶 ) = ( ∅ × 𝐶 ) ) |
8 |
|
0xp |
⊢ ( ∅ × 𝐶 ) = ∅ |
9 |
7 8
|
eqtrdi |
⊢ ( 𝐴 = ∅ → ( 𝐴 × 𝐶 ) = ∅ ) |
10 |
9
|
eqeq1d |
⊢ ( 𝐴 = ∅ → ( ( 𝐴 × 𝐶 ) = ( 𝐵 × 𝐶 ) ↔ ∅ = ( 𝐵 × 𝐶 ) ) ) |
11 |
|
eqcom |
⊢ ( ∅ = ( 𝐵 × 𝐶 ) ↔ ( 𝐵 × 𝐶 ) = ∅ ) |
12 |
10 11
|
bitrdi |
⊢ ( 𝐴 = ∅ → ( ( 𝐴 × 𝐶 ) = ( 𝐵 × 𝐶 ) ↔ ( 𝐵 × 𝐶 ) = ∅ ) ) |
13 |
12
|
adantr |
⊢ ( ( 𝐴 = ∅ ∧ 𝐶 ≠ ∅ ) → ( ( 𝐴 × 𝐶 ) = ( 𝐵 × 𝐶 ) ↔ ( 𝐵 × 𝐶 ) = ∅ ) ) |
14 |
|
df-ne |
⊢ ( 𝐶 ≠ ∅ ↔ ¬ 𝐶 = ∅ ) |
15 |
|
xpeq0 |
⊢ ( ( 𝐵 × 𝐶 ) = ∅ ↔ ( 𝐵 = ∅ ∨ 𝐶 = ∅ ) ) |
16 |
|
orel2 |
⊢ ( ¬ 𝐶 = ∅ → ( ( 𝐵 = ∅ ∨ 𝐶 = ∅ ) → 𝐵 = ∅ ) ) |
17 |
15 16
|
syl5bi |
⊢ ( ¬ 𝐶 = ∅ → ( ( 𝐵 × 𝐶 ) = ∅ → 𝐵 = ∅ ) ) |
18 |
14 17
|
sylbi |
⊢ ( 𝐶 ≠ ∅ → ( ( 𝐵 × 𝐶 ) = ∅ → 𝐵 = ∅ ) ) |
19 |
18
|
adantl |
⊢ ( ( 𝐴 = ∅ ∧ 𝐶 ≠ ∅ ) → ( ( 𝐵 × 𝐶 ) = ∅ → 𝐵 = ∅ ) ) |
20 |
13 19
|
sylbid |
⊢ ( ( 𝐴 = ∅ ∧ 𝐶 ≠ ∅ ) → ( ( 𝐴 × 𝐶 ) = ( 𝐵 × 𝐶 ) → 𝐵 = ∅ ) ) |
21 |
|
eqtr3 |
⊢ ( ( 𝐴 = ∅ ∧ 𝐵 = ∅ ) → 𝐴 = 𝐵 ) |
22 |
6 20 21
|
syl6an |
⊢ ( ( 𝐴 = ∅ ∧ 𝐶 ≠ ∅ ) → ( ( 𝐴 × 𝐶 ) = ( 𝐵 × 𝐶 ) → 𝐴 = 𝐵 ) ) |
23 |
|
xpeq1 |
⊢ ( 𝐴 = 𝐵 → ( 𝐴 × 𝐶 ) = ( 𝐵 × 𝐶 ) ) |
24 |
22 23
|
impbid1 |
⊢ ( ( 𝐴 = ∅ ∧ 𝐶 ≠ ∅ ) → ( ( 𝐴 × 𝐶 ) = ( 𝐵 × 𝐶 ) ↔ 𝐴 = 𝐵 ) ) |
25 |
5 24
|
sylanb |
⊢ ( ( ¬ 𝐴 ≠ ∅ ∧ 𝐶 ≠ ∅ ) → ( ( 𝐴 × 𝐶 ) = ( 𝐵 × 𝐶 ) ↔ 𝐴 = 𝐵 ) ) |
26 |
4 25
|
pm2.61ian |
⊢ ( 𝐶 ≠ ∅ → ( ( 𝐴 × 𝐶 ) = ( 𝐵 × 𝐶 ) ↔ 𝐴 = 𝐵 ) ) |