Description: Equality theorem for Cartesian product. (Contributed by FL, 31-Aug-2009)
| Ref | Expression | ||
|---|---|---|---|
| Assertion | xpeq12 | ⊢ ( ( 𝐴 = 𝐵 ∧ 𝐶 = 𝐷 ) → ( 𝐴 × 𝐶 ) = ( 𝐵 × 𝐷 ) ) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | xpeq1 | ⊢ ( 𝐴 = 𝐵 → ( 𝐴 × 𝐶 ) = ( 𝐵 × 𝐶 ) ) | |
| 2 | xpeq2 | ⊢ ( 𝐶 = 𝐷 → ( 𝐵 × 𝐶 ) = ( 𝐵 × 𝐷 ) ) | |
| 3 | 1 2 | sylan9eq | ⊢ ( ( 𝐴 = 𝐵 ∧ 𝐶 = 𝐷 ) → ( 𝐴 × 𝐶 ) = ( 𝐵 × 𝐷 ) ) |