Metamath Proof Explorer


Theorem 2thd

Description: Two truths are equivalent. Deduction form. (Contributed by NM, 3-Jun-2012)

Ref Expression
Hypotheses 2thd.1
|- ( ph -> ps )
2thd.2
|- ( ph -> ch )
Assertion 2thd
|- ( ph -> ( ps <-> ch ) )

Proof

Step Hyp Ref Expression
1 2thd.1
 |-  ( ph -> ps )
2 2thd.2
 |-  ( ph -> ch )
3 pm5.1im
 |-  ( ps -> ( ch -> ( ps <-> ch ) ) )
4 1 2 3 sylc
 |-  ( ph -> ( ps <-> ch ) )