Theorem 3com13

Description: Commutation in antecedent. Swap 1st and 3rd. (Contributed by NM, 28-Jan-1996) (Proof shortened by Wolf Lammen, 22-Jun-2022)

	Ref	Expression
Hypothesis	3exp.1	|- ( ( ph /\ ps /\ ch ) -> th )
Assertion	3com13	|- ( ( ch /\ ps /\ ph ) -> th )

Proof

Step	Hyp	Ref	Expression
1		3exp.1	|- ( ( ph /\ ps /\ ch ) -> th )
2	1	3exp	|- ( ph -> ( ps -> ( ch -> th ) ) )
3	2	3imp31	|- ( ( ch /\ ps /\ ph ) -> th )