Metamath Proof Explorer


Theorem 3eqtr3rd

Description: A deduction from three chained equalities. (Contributed by NM, 14-Jan-2006)

Ref Expression
Hypotheses 3eqtr3d.1
|- ( ph -> A = B )
3eqtr3d.2
|- ( ph -> A = C )
3eqtr3d.3
|- ( ph -> B = D )
Assertion 3eqtr3rd
|- ( ph -> D = C )

Proof

Step Hyp Ref Expression
1 3eqtr3d.1
 |-  ( ph -> A = B )
2 3eqtr3d.2
 |-  ( ph -> A = C )
3 3eqtr3d.3
 |-  ( ph -> B = D )
4 1 2 eqtr3d
 |-  ( ph -> B = C )
5 3 4 eqtr3d
 |-  ( ph -> D = C )