Theorem 3exp1

Description: Exportation from left triple conjunction. (Contributed by NM, 24-Feb-2005)

	Ref	Expression
Hypothesis	3exp1.1	|- ( ( ( ph /\ ps /\ ch ) /\ th ) -> ta )
Assertion	3exp1	|- ( ph -> ( ps -> ( ch -> ( th -> ta ) ) ) )

Proof

Step	Hyp	Ref	Expression
1		3exp1.1	|- ( ( ( ph /\ ps /\ ch ) /\ th ) -> ta )
2	1	ex	|- ( ( ph /\ ps /\ ch ) -> ( th -> ta ) )
3	2	3exp	|- ( ph -> ( ps -> ( ch -> ( th -> ta ) ) ) )