Metamath Proof Explorer


Theorem 3impcombi

Description: A 1-hypothesis propositional calculus deduction. (Contributed by Alan Sare, 25-Sep-2017)

Ref Expression
Hypothesis 3impcombi.1
|- ( ( ph /\ ps /\ ph ) -> ( ch <-> th ) )
Assertion 3impcombi
|- ( ( ps /\ ph /\ ch ) -> th )

Proof

Step Hyp Ref Expression
1 3impcombi.1
 |-  ( ( ph /\ ps /\ ph ) -> ( ch <-> th ) )
2 1 biimpd
 |-  ( ( ph /\ ps /\ ph ) -> ( ch -> th ) )
3 2 3anidm13
 |-  ( ( ph /\ ps ) -> ( ch -> th ) )
4 3 ancoms
 |-  ( ( ps /\ ph ) -> ( ch -> th ) )
5 4 3impia
 |-  ( ( ps /\ ph /\ ch ) -> th )