Metamath Proof Explorer


Theorem 3jaao

Description: Inference conjoining and disjoining the antecedents of three implications. (Contributed by Jeff Hankins, 15-Aug-2009) (Proof shortened by Andrew Salmon, 13-May-2011) (Proof shortened by Garrett Katz, 16-Jun-2026)

Ref Expression
Hypotheses 3jaao.1
|- ( ph -> ( ps -> ch ) )
3jaao.2
|- ( th -> ( ta -> ch ) )
3jaao.3
|- ( et -> ( ze -> ch ) )
Assertion 3jaao
|- ( ( ph /\ th /\ et ) -> ( ( ps \/ ta \/ ze ) -> ch ) )

Proof

Step Hyp Ref Expression
1 3jaao.1
 |-  ( ph -> ( ps -> ch ) )
2 3jaao.2
 |-  ( th -> ( ta -> ch ) )
3 3jaao.3
 |-  ( et -> ( ze -> ch ) )
4 3jao
 |-  ( ( ( ps -> ch ) /\ ( ta -> ch ) /\ ( ze -> ch ) ) -> ( ( ps \/ ta \/ ze ) -> ch ) )
5 1 2 3 4 syl3an
 |-  ( ( ph /\ th /\ et ) -> ( ( ps \/ ta \/ ze ) -> ch ) )