Description: Closed form of ancoms . The following user's proof is completed by invoking mmj2's unify command and using mmj2's StepSelector to pick all remaining steps of the Metamath proof.
| 1:: | |- ( ( ph /\ ps ) <-> ( ps /\ ph ) ) |
| qed:1,?: e0a | |- ( ( ( ph /\ ps ) -> ch ) <-> ( ( ps /\ ph ) -> ch ) ) |
| Ref | Expression | ||
|---|---|---|---|
| Assertion | ancomstVD | |- ( ( ( ph /\ ps ) -> ch ) <-> ( ( ps /\ ph ) -> ch ) ) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | ancom | |- ( ( ph /\ ps ) <-> ( ps /\ ph ) ) |
|
| 2 | imbi1 | |- ( ( ( ph /\ ps ) <-> ( ps /\ ph ) ) -> ( ( ( ph /\ ps ) -> ch ) <-> ( ( ps /\ ph ) -> ch ) ) ) |
|
| 3 | 1 2 | e0a | |- ( ( ( ph /\ ps ) -> ch ) <-> ( ( ps /\ ph ) -> ch ) ) |