Theorem cdeqi

Description: Deduce conditional equality. (Contributed by Mario Carneiro, 11-Aug-2016)

	Ref	Expression
Hypothesis	cdeqi.1	|- ( x = y -> ph )
Assertion	cdeqi	|- CondEq ( x = y -> ph )

Proof

Step	Hyp	Ref	Expression
1		cdeqi.1	|- ( x = y -> ph )
2		df-cdeq	|- ( CondEq ( x = y -> ph ) <-> ( x = y -> ph ) )
3	1 2	mpbir	|- CondEq ( x = y -> ph )