Metamath Proof Explorer


Theorem com24

Description: Commutation of antecedents. Swap 2nd and 4th. Deduction associated with com13 . (Contributed by NM, 25-Apr-1994) (Proof shortened by Wolf Lammen, 28-Jul-2012)

Ref Expression
Hypothesis com4.1
|- ( ph -> ( ps -> ( ch -> ( th -> ta ) ) ) )
Assertion com24
|- ( ph -> ( th -> ( ch -> ( ps -> ta ) ) ) )

Proof

Step Hyp Ref Expression
1 com4.1
 |-  ( ph -> ( ps -> ( ch -> ( th -> ta ) ) ) )
2 1 com4t
 |-  ( ch -> ( th -> ( ph -> ( ps -> ta ) ) ) )
3 2 com13
 |-  ( ph -> ( th -> ( ch -> ( ps -> ta ) ) ) )