Metamath Proof Explorer


Theorem elpr2

Description: A member of a pair of sets is one or the other of them, and conversely. Exercise 1 of TakeutiZaring p. 15. (Contributed by NM, 14-Oct-2005) (Proof shortened by JJ, 23-Jul-2021)

Ref Expression
Hypotheses elpr2.1
|- B e. _V
elpr2.2
|- C e. _V
Assertion elpr2
|- ( A e. { B , C } <-> ( A = B \/ A = C ) )

Proof

Step Hyp Ref Expression
1 elpr2.1
 |-  B e. _V
2 elpr2.2
 |-  C e. _V
3 elpr2g
 |-  ( ( B e. _V /\ C e. _V ) -> ( A e. { B , C } <-> ( A = B \/ A = C ) ) )
4 1 2 3 mp2an
 |-  ( A e. { B , C } <-> ( A = B \/ A = C ) )