Theorem exp5l

Description: An exportation inference. (Contributed by Jeff Hankins, 7-Jul-2009)

	Ref	Expression
Hypothesis	exp5l.1	|- ( ph -> ( ( ( ps /\ ch ) /\ ( th /\ ta ) ) -> et ) )
Assertion	exp5l	|- ( ph -> ( ps -> ( ch -> ( th -> ( ta -> et ) ) ) ) )

Proof

Step	Hyp	Ref	Expression
1		exp5l.1	|- ( ph -> ( ( ( ps /\ ch ) /\ ( th /\ ta ) ) -> et ) )
2	1	expd	|- ( ph -> ( ( ps /\ ch ) -> ( ( th /\ ta ) -> et ) ) )
3	2	exp5c	|- ( ph -> ( ps -> ( ch -> ( th -> ( ta -> et ) ) ) ) )