Metamath Proof Explorer


Theorem imaeq2d

Description: Equality theorem for image. (Contributed by FL, 15-Dec-2006)

Ref Expression
Hypothesis imaeq1d.1
|- ( ph -> A = B )
Assertion imaeq2d
|- ( ph -> ( C " A ) = ( C " B ) )

Proof

Step Hyp Ref Expression
1 imaeq1d.1
 |-  ( ph -> A = B )
2 imaeq2
 |-  ( A = B -> ( C " A ) = ( C " B ) )
3 1 2 syl
 |-  ( ph -> ( C " A ) = ( C " B ) )