Metamath Proof Explorer


Theorem orcoms

Description: Commutation of disjuncts in antecedent. (Contributed by NM, 2-Dec-2012)

Ref Expression
Hypothesis orcoms.1
|- ( ( ph \/ ps ) -> ch )
Assertion orcoms
|- ( ( ps \/ ph ) -> ch )

Proof

Step Hyp Ref Expression
1 orcoms.1
 |-  ( ( ph \/ ps ) -> ch )
2 pm1.4
 |-  ( ( ps \/ ph ) -> ( ph \/ ps ) )
3 2 1 syl
 |-  ( ( ps \/ ph ) -> ch )