Metamath Proof Explorer


Theorem oveqan12d

Description: Equality deduction for operation value. (Contributed by NM, 10-Aug-1995)

Ref Expression
Hypotheses oveq1d.1
|- ( ph -> A = B )
opreqan12i.2
|- ( ps -> C = D )
Assertion oveqan12d
|- ( ( ph /\ ps ) -> ( A F C ) = ( B F D ) )

Proof

Step Hyp Ref Expression
1 oveq1d.1
 |-  ( ph -> A = B )
2 opreqan12i.2
 |-  ( ps -> C = D )
3 oveq12
 |-  ( ( A = B /\ C = D ) -> ( A F C ) = ( B F D ) )
4 1 2 3 syl2an
 |-  ( ( ph /\ ps ) -> ( A F C ) = ( B F D ) )