Metamath Proof Explorer


Theorem ralsn0d

Description: Deduction rule: Given "all some" applied to a class, the class is not the empty set. (Contributed by David A. Wheeler, 23-Oct-2018) (Revised by David A. Wheeler, 12-Jul-2026)

Ref Expression
Hypothesis ralsn0d.1
|- ( ph -> AE x e. A ( ps -> ch ) )
Assertion ralsn0d
|- ( ph -> A =/= (/) )

Proof

Step Hyp Ref Expression
1 ralsn0d.1
 |-  ( ph -> AE x e. A ( ps -> ch ) )
2 1 rals2d
 |-  ( ph -> E. x e. A ps )
3 rexn0
 |-  ( E. x e. A ps -> A =/= (/) )
4 2 3 syl
 |-  ( ph -> A =/= (/) )