Metamath Proof Explorer


Theorem rightoldd

Description: An element of a right set is an element of the old set. (Contributed by Scott Fenton, 27-Feb-2026)

Ref Expression
Hypothesis rightel.1
|- ( ph -> A e. ( _Right ` B ) )
Assertion rightoldd
|- ( ph -> A e. ( _Old ` ( bday ` B ) ) )

Proof

Step Hyp Ref Expression
1 rightel.1
 |-  ( ph -> A e. ( _Right ` B ) )
2 rightold
 |-  ( A e. ( _Right ` B ) -> A e. ( _Old ` ( bday ` B ) ) )
3 1 2 syl
 |-  ( ph -> A e. ( _Old ` ( bday ` B ) ) )