Theorem rneqd

Description: Equality deduction for range. (Contributed by NM, 4-Mar-2004)

	Ref	Expression
Hypothesis	rneqd.1	|- ( ph -> A = B )
Assertion	rneqd	|- ( ph -> ran A = ran B )

Proof

Step	Hyp	Ref	Expression
1		rneqd.1	|- ( ph -> A = B )
2		rneq	|- ( A = B -> ran A = ran B )
3	1 2	syl	|- ( ph -> ran A = ran B )