Metamath Proof Explorer


Theorem simprd

Description: Deduction eliminating a conjunct. (Contributed by NM, 14-May-1993) A translation of natural deduction rule /\ ER ( /\ elimination right), see natded . (Proof shortened by Wolf Lammen, 3-Oct-2013)

Ref Expression
Hypothesis simprd.1
|- ( ph -> ( ps /\ ch ) )
Assertion simprd
|- ( ph -> ch )

Proof

Step Hyp Ref Expression
1 simprd.1
 |-  ( ph -> ( ps /\ ch ) )
2 1 ancomd
 |-  ( ph -> ( ch /\ ps ) )
3 2 simpld
 |-  ( ph -> ch )