Metamath Proof Explorer


Theorem sq0

Description: The square of 0 is 0. (Contributed by NM, 6-Jun-2006)

Ref Expression
Assertion sq0
|- ( 0 ^ 2 ) = 0

Proof

Step Hyp Ref Expression
1 eqid
 |-  0 = 0
2 0cn
 |-  0 e. CC
3 2 sqeq0i
 |-  ( ( 0 ^ 2 ) = 0 <-> 0 = 0 )
4 1 3 mpbir
 |-  ( 0 ^ 2 ) = 0