Metamath Proof Explorer


Theorem xrneq1d

Description: Equality theorem for the range Cartesian product, deduction form. (Contributed by Peter Mazsa, 7-Sep-2021)

Ref Expression
Hypothesis xrneq1d.1
|- ( ph -> A = B )
Assertion xrneq1d
|- ( ph -> ( A |X. C ) = ( B |X. C ) )

Proof

Step Hyp Ref Expression
1 xrneq1d.1
 |-  ( ph -> A = B )
2 xrneq1
 |-  ( A = B -> ( A |X. C ) = ( B |X. C ) )
3 1 2 syl
 |-  ( ph -> ( A |X. C ) = ( B |X. C ) )