Metamath Proof Explorer


Theorem xrneq2d

Description: Equality theorem for the range Cartesian product, deduction form. (Contributed by Peter Mazsa, 7-Sep-2021)

Ref Expression
Hypothesis xrneq2d.1
|- ( ph -> A = B )
Assertion xrneq2d
|- ( ph -> ( C |X. A ) = ( C |X. B ) )

Proof

Step Hyp Ref Expression
1 xrneq2d.1
 |-  ( ph -> A = B )
2 xrneq2
 |-  ( A = B -> ( C |X. A ) = ( C |X. B ) )
3 1 2 syl
 |-  ( ph -> ( C |X. A ) = ( C |X. B ) )