Metamath Proof Explorer


Theorem 1p4e5

Description: 1 + 4 = 5. (Contributed by SN, 24-Aug-2026)

Ref Expression
Assertion 1p4e5 1 + 4 = 5

Proof

Step Hyp Ref Expression
1 df-4 4 = 3 + 1
2 1 oveq2i 1 + 4 = 1 + 3 + 1
3 ax-1cn 1
4 3cn 3
5 3 4 3 addassi 1 + 3 + 1 = 1 + 3 + 1
6 1p3e4 1 + 3 = 4
7 6 oveq1i 1 + 3 + 1 = 4 + 1
8 4p1e5 4 + 1 = 5
9 7 8 eqtri 1 + 3 + 1 = 5
10 2 5 9 3eqtr2i 1 + 4 = 5