Metamath Proof Explorer


Theorem 1p5e6

Description: 1 + 5 = 6. (Contributed by SN, 24-Aug-2026)

Ref Expression
Assertion 1p5e6 1 + 5 = 6

Proof

Step Hyp Ref Expression
1 df-5 5 = 4 + 1
2 1 oveq2i 1 + 5 = 1 + 4 + 1
3 ax-1cn 1
4 4cn 4
5 3 4 3 addassi 1 + 4 + 1 = 1 + 4 + 1
6 1p4e5 1 + 4 = 5
7 6 oveq1i 1 + 4 + 1 = 5 + 1
8 5p1e6 5 + 1 = 6
9 7 8 eqtri 1 + 4 + 1 = 6
10 2 5 9 3eqtr2i 1 + 5 = 6