Metamath Proof Explorer


Theorem 1p6e7

Description: 1 + 6 = 7. (Contributed by SN, 24-Aug-2026)

Ref Expression
Assertion 1p6e7 1 + 6 = 7

Proof

Step Hyp Ref Expression
1 df-6 6 = 5 + 1
2 1 oveq2i 1 + 6 = 1 + 5 + 1
3 ax-1cn 1
4 5cn 5
5 3 4 3 addassi 1 + 5 + 1 = 1 + 5 + 1
6 1p5e6 1 + 5 = 6
7 6 oveq1i 1 + 5 + 1 = 6 + 1
8 6p1e7 6 + 1 = 7
9 7 8 eqtri 1 + 5 + 1 = 7
10 2 5 9 3eqtr2i 1 + 6 = 7