Metamath Proof Explorer


Theorem 3jaob

Description: Disjunction of three antecedents. (Contributed by NM, 13-Sep-2011) (Proof shortened by Hongxiu Chen, 29-Jun-2025)

Ref Expression
Assertion 3jaob ⊢ φ ∨ χ ∨ θ → ψ ↔ φ → ψ ∧ χ → ψ ∧ θ → ψ

Proof

Step Hyp Ref Expression
1 pm5.53 ⊢ φ ∨ χ ∨ θ → ψ ↔ φ → ψ ∧ χ → ψ ∧ θ → ψ
2 df-3or ⊢ φ ∨ χ ∨ θ ↔ φ ∨ χ ∨ θ
3 2 imbi1i ⊢ φ ∨ χ ∨ θ → ψ ↔ φ ∨ χ ∨ θ → ψ
4 df-3an ⊢ φ → ψ ∧ χ → ψ ∧ θ → ψ ↔ φ → ψ ∧ χ → ψ ∧ θ → ψ
5 1 3 4 3bitr4i ⊢ φ ∨ χ ∨ θ → ψ ↔ φ → ψ ∧ χ → ψ ∧ θ → ψ