Metamath Proof Explorer


Theorem 3sstr4i

Description: Substitution of equality in both sides of a subclass relationship. (Contributed by NM, 13-Jan-1996) (Proof shortened by Eric Schmidt, 26-Jan-2007)

Ref Expression
Hypotheses 3sstr4.1 AB
3sstr4.2 C=A
3sstr4.3 D=B
Assertion 3sstr4i CD

Proof

Step Hyp Ref Expression
1 3sstr4.1 AB
2 3sstr4.2 C=A
3 3sstr4.3 D=B
4 2 3 sseq12i CDAB
5 1 4 mpbir CD