Metamath Proof Explorer


Theorem 3sstr4i

Description: Substitution of equality in both sides of a subclass relationship. (Contributed by NM, 13-Jan-1996) (Proof shortened by Eric Schmidt, 26-Jan-2007)

Ref Expression
Hypotheses 3sstr4.1 A B
3sstr4.2 C = A
3sstr4.3 D = B
Assertion 3sstr4i C D

Proof

Step Hyp Ref Expression
1 3sstr4.1 A B
2 3sstr4.2 C = A
3 3sstr4.3 D = B
4 2 3 sseq12i C D A B
5 1 4 mpbir C D