Metamath Proof Explorer


Theorem 4lt5

Description: 4 is less than 5. (Contributed by Mario Carneiro, 15-Sep-2013)

Ref Expression
Assertion 4lt5 ⊢ 4 < 5

Proof

Step Hyp Ref Expression
1 4re ⊢ 4 ∈ ℝ
2 1 ltp1i ⊢ 4 < 4 + 1
3 df-5 ⊢ 5 = 4 + 1
4 2 3 breqtrri ⊢ 4 < 5