Metamath Proof Explorer


Theorem 4p2e6

Description: 4 + 2 = 6. (Contributed by NM, 11-May-2004)

Ref Expression
Assertion 4p2e6 4+2=6

Proof

Step Hyp Ref Expression
1 df-2 2=1+1
2 1 oveq2i 4+2=4+1+1
3 4cn 4
4 ax-1cn 1
5 3 4 4 addassi 4+1+1=4+1+1
6 2 5 eqtr4i 4+2=4+1+1
7 df-5 5=4+1
8 7 oveq1i 5+1=4+1+1
9 6 8 eqtr4i 4+2=5+1
10 df-6 6=5+1
11 9 10 eqtr4i 4+2=6