Metamath Proof Explorer


Theorem abslti

Description: Absolute value and 'less than' relation. (Contributed by NM, 6-Apr-2005)

Ref Expression
Hypotheses sqrtthi.1 ⊢ A ∈ ℝ
sqr11.1 ⊢ B ∈ ℝ
Assertion abslti ⊢ A < B ↔ − B < A ∧ A < B

Proof

Step Hyp Ref Expression
1 sqrtthi.1 ⊢ A ∈ ℝ
2 sqr11.1 ⊢ B ∈ ℝ
3 abslt ⊢ A ∈ ℝ ∧ B ∈ ℝ → A < B ↔ − B < A ∧ A < B
4 1 2 3 mp2an ⊢ A < B ↔ − B < A ∧ A < B