Metamath Proof Explorer


Theorem absvalsqd

Description: Square of value of absolute value function. (Contributed by Mario Carneiro, 29-May-2016)

Ref Expression
Hypothesis abscld.1 ⊢ φ → A ∈ ℂ
Assertion absvalsqd ⊢ φ → A 2 = A ⁢ A ‾

Proof

Step Hyp Ref Expression
1 abscld.1 ⊢ φ → A ∈ ℂ
2 absvalsq ⊢ A ∈ ℂ → A 2 = A ⁢ A ‾
3 1 2 syl ⊢ φ → A 2 = A ⁢ A ‾