Metamath Proof Explorer


Theorem absvalsq2d

Description: Square of value of absolute value function. (Contributed by Mario Carneiro, 29-May-2016)

Ref Expression
Hypothesis abscld.1 ⊢ φ → A ∈ ℂ
Assertion absvalsq2d ⊢ φ → A 2 = ℜ ⁡ A 2 + ℑ ⁡ A 2

Proof

Step Hyp Ref Expression
1 abscld.1 ⊢ φ → A ∈ ℂ
2 absvalsq2 ⊢ A ∈ ℂ → A 2 = ℜ ⁡ A 2 + ℑ ⁡ A 2
3 1 2 syl ⊢ φ → A 2 = ℜ ⁡ A 2 + ℑ ⁡ A 2