Metamath Proof Explorer


Theorem aevlem0

Description: Lemma for aevlem . Instance of aev . (Contributed by NM, 8-Jul-2016) (Proof shortened by Wolf Lammen, 17-Feb-2018) Remove dependency on ax-12 . (Revised by Wolf Lammen, 14-Mar-2021) (Revised by BJ, 29-Mar-2021) (Proof shortened by Wolf Lammen, 30-Mar-2021)

Ref Expression
Assertion aevlem0 xx=yzz=x

Proof

Step Hyp Ref Expression
1 spaev xx=yx=y
2 1 alrimiv xx=yzx=y
3 cbvaev xx=yzz=y
4 equeuclr x=yz=yz=x
5 4 al2imi zx=yzz=yzz=x
6 2 3 5 sylc xx=yzz=x