Metamath Proof Explorer


Theorem aevlem0

Description: Lemma for aevlem . Instance of aev . (Contributed by NM, 8-Jul-2016) (Proof shortened by Wolf Lammen, 17-Feb-2018) Remove dependency on ax-12 . (Revised by Wolf Lammen, 14-Mar-2021) (Revised by BJ, 29-Mar-2021) (Proof shortened by Wolf Lammen, 30-Mar-2021)

Ref Expression
Assertion aevlem0 x x = y z z = x

Proof

Step Hyp Ref Expression
1 spaev x x = y x = y
2 1 alrimiv x x = y z x = y
3 cbvaev x x = y z z = y
4 equeuclr x = y z = y z = x
5 4 al2imi z x = y z z = y z z = x
6 2 3 5 sylc x x = y z z = x